Riemann surfaces of f(z)=z^(1/2) Posted on 2019/05/23 by Carl Robitaille https://www.geogebra.org/m/mqe4gddn Riemann surfaces of f(z)=z^(1/2) with @geogebra #complex #functions #riemann #surrfaces pic.twitter.com/Twq5WmdsXi— ∞ Juan Carlos (@jcponcemath) May 23, 2019